Notebook Entry - 080303

Finished Views


finished view at pentagon intersection  

finished view at triangle intersection  

first set of spindles placed at right angles to each other  

first set of spindles creates a neat swirl around a hexagon  

two sets of spindles around the same hexagon  

the structure created around the equator with the hexagons being N and S  

Source

none

Classification

C10, 32 multipole, spindle, interlocked,

Size

29cm circumference

Materials

Wrap
light blue cone thread
Marking
Kreinik gold cord
Design threads
#5 perle cotton yellow-orange (DMC972), orange (DMC351), fuscia (DMC718), purple (Anchor102), green (Anchor 189)
Rainbow Gallery Gold Rush 18 blue

Division/Marking

C10 with 32 pole support lines

Diagrams


red outline of shape, blue line shows start for spindle  

location of second spindle in sequence  

Directions

  1. Wrap mari and mark a 32 pole.
  2. Stitch the first spindle in one of the colors, starting and ending with one row of the blue metallic.
  3. Use the same color and place the next spindle at a right angle to the first one. See second diagram.
  4. Continue to use the same color and place the spindles at right angles to each other until you have placed 6 spindles. They will not cross each other and there will be one spindle end in each pentagon.
  5. Choose your next color and work a spindle in the next place at any pentagon.
  6. Once again, keep using the same color and place the spindles at right angles to each other until you have completed 6 spindles in that color.
  7. Repeat with the other three colors.

Notes

This is the second iteration of the design in #080302. I like it in the bright colors much better. The coloring described here ends up demonstrating how you can embed five different octahedra within a dodecahedron. It is much easier to do than the Conway solution that I used in the previous one.

After finishing this one I noticed that I could probably do a dual design where the spindles go along the edges of the pentagons rather than the triangles. They would intersect at the hexagons. Interestingly I can still use the coloring method of embedded octahedra. In the original the octahedra lines end up being along lines of the 32 marking, but in this case they would be along lines of the C10 and I don't think I would need to do the 32 marking at all.

Given To

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